Explanation: you can ignore the 7 because multiplying #csc (4x)# by a constant doesn't change whether a y-value exists at that point or not.

Mar 30, 2018 · Match each equation number with a equivalent letter, and then prove each one. (1.): (csc (x) - sin (x)) (2.): (sin (x)/ (sin (x)+ cos (x)) (3.): (2 sin 4 (x)) (cos 4 ...

They aren't different. Here is the graph of cot (x) with asymptotes at x = n pi: graph {cot (x) [-10, 10, -5, 5]} Here is the graph of 1/tan (x) with asymptotes at x = n pi: graph {1/ (tan (x)) [-10, 10, …

Given: csc (y) (sin (y)-1) = 1-csc (y) Use the distributive property on the left side: csc (y)sin (y)-csc (y) = 1-csc (y) Use the identity 1 = csc (x)sin (x): 1-csc (y) = 1-csc (y) The original equation is …

f (x)=csc x- sin x is CONVEX at x=pi/3 From the given equation f (x)=csc x- sin x We determine f'' (x), the second derivative of f (x) after which , we test if f'' (pi/3)>0, if True then CONVEX.

May 25, 2018 · Explanation: writing your equation in the form #csc (x) (3cot^2 (x)-1)=0# so we get #csc (x)=0# or #cot (x)=pm1/sqrt (3)# Answer link Nghi N. · Jacobi J. May 25, 2018 #x = (2pi)/3#

Apr 3, 2018 · Verified below Using cos2x= 1-2sin^2x 1/sinx= cscx Start: (cos2x)/ (sin²x)=csc² x-2 (1-2sin^2x)/ (sin²x)=csc² x-2 1/sin^2x- (2sin^2x)/sin^2x=csc² x-2 csc^2x-2=csc² x-2

We know that the derivative of #cot (x)# is #-csc^2 (x)#, so we can add a minus sign both outside and inside the integral (so they cancel) to work it out: #-int\ -csc^2 (x)\ dx-x=-cot (x)-x+C# …

An object with a mass of 6kg is pushed along a linear path with a kinetic friction coefficient of uk(x) = 2 + csc x. How much work would it take to move the object over #x in [pi/8, (3pi)/8], where x …

Please see below. Find f'(x) if f(x)=(sinxsecx)/(1+x tan x) There are several ways to proceed. Here is the one I prefer. f(x)=(sinxsecx)/(1+x tan x) = tanx/(1+xtanx) Multiply numerator and …